(1-w-w²)⁶=64 prove thta

1−w−w2=64

Step 1: Simplify both sides of the equation.

−w2−w+1=64

Step 2: Subtract 64 from both sides.

−w2−w+1−64=64−64

−w2−w−63=0

For this equation: a=-1, b=-1, c=-63

−1w2+−1w+−63=0

Step 3: Use quadratic formula with a=-1, b=-1, c=-63.

w= −b±√b2−4ac /2a

w= −(−1)±√(−1)2−4(−1)(−63) /2(−1)

w= 1±√−251/ −2

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

step-by-step explanation: