Please help me solve these problems tanA - secA =

1. (SinA - 1)/ CosA

2. (Sin²A - CosA)/ CosA

3. (Cos²A - 1)/ CosA

cos B cot B - tan B =

1. (Cos²B - SinB)/ SinB CosB

2. (Sin²B - CosB)/ SinB

3. (Cos³B - Sin²B)/ SinB CosB

sec B cot B =

1. cosB/sin²B

2. 1/sinB

3. sinB/cos²B

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.