In the graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded and labeled B, and the area where f(x) and g(x) have shading in common is labeled AB. Graph of two intersecting lines. One line g of x is solid and goes through the points 0, 2, negative 2, 4 and is shaded in below the line. The other line f of x is solid, and goes through the points 0, 2, 2, 0 and is shaded in below the line.

The graph represents which system of inequalities?

y ≤ −2x + 3
y ≤ x + 3
y ≥ −2x + 3
y ≥ x + 3
y ≤ −3x + 2
y ≤ −x + 2
y > −2x + 3
y > x + 3

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

dude thats to long figure it

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

answer: the answer is fre sha voca do

step-by-step explanation: