PLEASE HELP write the equation in slope-intercept form of the line that passes through (6,-11) and is perpendicular to the graph of y=-2/3x+12

I believe the equation would be: y=3/2x-20

Step-by-step explanation:

This is true because, first you would need to find the slope from the equation, which is -2/3. But, for perpendicular, you would need to make it the exact opposite (which is this case would leave you with a slope of 3/2)

Ex: if you had -3/4, the slope for one that is perpendicular would be 4/3 (exact opposite)

After finding the slope, you take the points (6,-11) and plug it into the equation "y-y1=m(x-x1)"

y-y1=m(x-x1)

y+11=3/2(x-6)

-distribute the 3/2-

y+11=3/2x-18/2

y+11=3/2x-9

-subtract 11 on both sides-

y=3/2x-20

Im not sure if all calculations are correct, but I hope this helps! :)

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)