Write the equation of the line that passes through the point (4,5) and is perpendicular to the graph of y=2x-3

Hello there! :)

We are given that the line passes through the point (4,5) and that it's perpendicular to the line y=2x-3.

Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, make it negative, and flop it over:

2

-2

-1/2

So the slope of the line perpendicular to y=2x-3 is -1/2.

Now, we have the slope and a point that the line passes through, so we can write the equation in point-slope form, which looks like so:

y-y1=m(x-x1)

Where

y1 is the y-coordinate of the point

m is the slope

x1 is the x-coordinate of the point

Now, let's plug our values into the equation:

y-y1=m(x-x1)

y-5=-1/2(x-4)

y-5=-1/2x+2

y=-1/2x+2+5

y=-1/2x+7

Hence, that is the equation of the line.

Hope it helps.

~A lonely teen who helps others with a smile

-Grace :-)

Good luck.