You have the cards numbered 1-10 in front of you. Each time you select a card, it is returned. What is the
probability of selecting a 3 and then an even number?
Circle one. Indenendent/Dependent

p> q if you calculate p is100 q is 79

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

6e14 is the answer.

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.