PLEASE HELP! ILL GIVE BRAINIEST!!! A spinner is divided into 10 equal sections numbered 1-10. Find the probability of spinning a 1, 3, or eight. Write your answer as a fraction, percent, and decimal.

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Given: m∠ adb = m∠cdb ad ≅ dc prove: m∠ bac = m∠bca lol

The fraction 7/9 is equivalent to a percent that is greater than 100%. truefalse