A man of height 1.5 m standing on top a building of height 48.5 m view another building of height 48.5 m views another building across the square. He observes that the angle of depression of the base of the building is 40° and the angle of depression of the top of the building is 25°. Both buildings stand on the same level ground. a) Calculate the distance of the man from the base of the building across the square measured along his line of sight.

could you reply to this with the question so i can ?

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

-1/3(x+1)^5

i’m pretty sure this is correct