Quadrilateral ABCD has coordinates A(-2,0), B(0,4), C(4, 6), and D(2, 2). Graph and label quadrilateral ABCD, and then graph and label the image
Rx-axis (ABCD) = A'B'C'D'.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

using pemdas, (order of operations) you'll see the answer is 24.

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