Help please!! I will mark brainilist and give a lot of points. This is Pythagorean theorem.

Formula: a^2+b^2=c^2

When I say ^2 I mean to the power of 2.

The question is asking me to solve for a.

Then give me b and c which is b = 17 1/3 and c = 16.

How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?

Unless I’m wrong.

Please help my solve this :D

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

4932,9180,7625 are divisible by 9