There are two parts to the following question. First, answer part A. Then, answer part B. Brianna and Gavin used partial quotients to show 552 -- 23. See their work below. Brianna's work Step 1: Subtract (20 x 23) from 552 to get 92. Step 2: Subtract (4 x 23) from 92 to get 0. Step 3. Add partial quotients Gavin's work Step 1: Subtract (10 x 23) from 552 to get 322 Step 2: Subtract (10 x 23) from 322 to get 92 Step 3: Subtract (2 x 23) from 92 to get 46. Step 4: Subtract (2 x 23) from 46 to get 0. Step 5: Add the partial quotients. Part A Which student(s) correctly calculated the quotient? Explain your answer. Can someone help?

b is the answer that makes most sense

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

middle maybe?

step-by-step explanation: