The perimeter of a rectangle is 56 centimeters. If the length of the rectangle is four centimeters less than three times its width, what are the dimensions of the rectangle?

Let the length be x and the width be y, then

2x + 2y = 56

x + y = 28 . . . (1)

x = 4 + 3y . . . (2)

Putting (2) into (1) gives

4 + 3y + y = 28

4y = 28 - 4 = 24

y = 24/4 = 6

x = 4 + 3(6) = 4 + 18 = 22

Therefore, length is 22 inches and width is 6 inches.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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