Hello how do you solve 5^-x = 6?

x = -log 6/log 5

Step-by-step explanation:

When the variable is in te exponent, logarithms help solve the equation very often.

5^-x = 6

Take the log of both sides.

log (5^-x) = log 6

Use the law of log of a power.

-x log 5 = log 6

-x = log 6/log 5

x = -log 6/log 5

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: