1. m_ADC=3x+10 and m~BC=2X-30,what is m™AC 2. m2BDC=3(x-5) and m--BC=x+25,what is MZA
3. m2A= 1/2 (x-10)and m_C=1/3 x+5,find m-BC
4. if m(BC)=4x-6 and m_C=x+10,waht is m_BDC?

What is the solution to the inequality? 6x−5> −29, a x> −4 bx> 4 cx< 4 dx< −4

Maria found the least common multiple of 6 and 15. her work is shown below. multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . multiples of 15: 15, 30, 45, 60, . . the least common multiple is 60. what is maria's error?

Tan198=asin164=? how to solve this? ?