Brooke has a savings account. The account balance is $550.87 at the beginning of the month. The list below shoes all of the activity for one month. - a deposit of $75.98
- a withdrawal of $34.88
- a deposit of $84.12

What is the balance in Brooke's savings account at the end of the month?

676.09

Step-by-step explanation:

550.87 + 75.98 = 626.85

626.85 - 34.88 = 591.97

591.97 + 84.12 = 676.09 therefore that's the amount at the end of the month

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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step-by-step explanation: