If the product of two positive numbers is 56. If their difference is 10 find the numbers

smaller --- x

larger x+10

x(x+10) = 56

x^2 + 10x = 56

x^2 + 10x + 25 = 56 + 25

(x+5)^2 = 81

x+5 = 9

x=4

one is 4, the other is 14

Hope this helps you!

x=33 ; y=23

Step-by-step explanation:

Given that x+y=56 and x-y=10

Solve for either variable.

x=y+10

Substitute, replace, your solved variable in the other equation

(y+10)+y=56    Subtract 10 on both sides

2y=46     Divide by 2

y=23        Substitute answer into a given equation

x+23=56    Subtract 23 on both sides

x=33

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer: it's d

step-by-step explanation: