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Mathematics, 23.11.2021 01:00 lillypierre8796

Find the value of $6+\frac{1}{2+\frac{1}{6+\frac{1}{2+\frac{1}{6+\cdots}}}}$. Your answer will be of the form $a+b\sqrt{c}$ where no factor of $c$ (other than $1$) is a square. Find $a+b+c$.

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