Side AB of a parallelogram ABCD is produced upto point E. If m<CBE = 35°, find m<ADC.

The measure of ∠ADC = 145°

Step-by-step explanation:

ABCD is a Parallelogram.

AB is produced to E .

∠CBE = 35°

We know that

∠ABC + <CBE = 180

Since , they are linear pair

➜ ∠ABC + 35° = 180°

➜ ∠ABC = 180°-35°

➜ ∠ABC = 145°

We know that

In a Parallelogram, Opposite angles are equal.

➜ The opposite angle of ∠ABC = ∠ADC

➜ ∠ADC = 145°

Therefore, The measure of ∠ADC = 145°

Similar Questions

In the accompanying diagram of the parallelogram ABCD, AB is extended to E such that CB is congruent to CE. If m< ADC = 100, what is m<CEB?

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

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region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true