2sin²θ+2sin²2θ = 3sin²2θ
Solve the equation for 0≤θ< 2π
Show steps...
Mathematics, 13.11.2021 14:00 amazinga
2sin²θ+2sin²2θ = 3sin²2θ
Solve the equation for 0≤θ< 2π
Show steps
Answers: 1
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