A driver travels for four days and covers 900 km in total. he covers 223 km, 188 km and 309 km on the first three days. how far does he travel on day 4

i guess for this it would go like:-

total distance covered by the driver in four days(d)= 900km

distance covered by him in first day(d1) = 223 km

distance covered by him on second day(d2) =188km

distance covered by him on third day(d3)= 309 km

now,

 distance covered on fourth day (d4)= 900-223-188-309

                                                             = 180 km

Step-by-step explanation:

here, the total distance is given i.e 900 km. similarly the distance covered by the driver on the consecutive days are also giver. so here we subract the distance covered by the driver in all the three days from the total distance it covers. it would gibe us the distance covered by him on the fourth day. since, it is the the left out distance that the driver has to cover.

hope it helps..

%40

step-by-step explanation:

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: