If you help me you get

3 ( 917 ) = 3 ( 900 ) + 3 ( 10 ) + 3 ( 7 )

5 ( 209 ) = 5 ( 200 ) + 5 ( 0 ) + 5 ( 9 )

6 ( 347 ) = 6 ( 300 ) + 6 ( 40 ) + 6 ( 7 )

9 ( 821 ) = 9 ( 800 ) + 9 ( 20 ) + 9 ( 1 )

11 ( 142 ) = 11 ( 100 ) + 11 ( 40 ) + 11 ( 2 )

Step-by-step explanation:

Hint(look at the first number in each part and math it with the first number in each answer.) For example, 3(937), the distributive property for that one would be 3(900) + 3(30) + 3(7). Then for 5(209) it would be 5(200) + 5(0) + 5(9), then for 6(342), it would be 6(300) + 6(40) + 6(2). Then for 9(821), it would be 9(800) + 9(20) + 9(1), and for the last one it would be 11(143), it would be 11(140) + 11(40) + 11(3). You basically distribute each amount into different place values.

Step-by-step explanation:

Hope it helps. Mark brainiest if it does!

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]