Abbotsford 17 km
Kelso
15 km
2
Hawick
What is the distance from Hawick to Kelso?
Round your answer to the nearest tenth of a kilometer.

a^2 + b^2 = c^2

Step-by-step explanation:

The distance from Abbotsford to Kelso is 17 km. That is your "a" value. The distance from Abbotsford to Hawick is 15 km.

Town B  is 26 miles from town A at a bearing of S15 W. Town C  is 54 miles from town A at a bearing of S7 E . Compute the distance from town B to town C Round your final answer to the nearest mile.

Step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq