2. Calculate the equation of the following line. ?

A. y= -3/2x + 7/2

B. y = 7/2 x - 3/ 2

C. y= 3/2x + 13/2

D. y= -3/2x + 3

1/y=72/x+3/y=17(x=0 and y=0) by TopprSimplify given equations:Let 1/x=u and 1/y=v1/x+1/y=7 impliesu+v=72/x+3/y=17 implies2u+3v=17New set of equation is:u+v=7...(1)2u+3v=17...(2)From equation (1):a 1 =1,b 1 =1 and c 1 =−7From equation (2):a 2 =2,b 2 =3 and c 2 =−17Using cross multiplication method:−17+21u = −14+17v = 3−21 4u =1 and 3v =1u=4 and q=3x=1/4 nad y=1/3 [Since we consider p=1/x and q=1/y]Answer x=1/4,y=1/32/x+3/y=17(x=0 and y=0) by TopprSimplify given equations:Let 1/x=u and 1/y=v1/x+1/y=7 impliesu+v=72/x+3/y=17 implies2u+3v=17New set of equation is:u+v=7...(1)2u+3v=17...(2)From equation (1):a 1 =1,b 1 =1 and c 1 =−7From equation (2):a 2 =2,b 2 =3 and c 2 =−17Using cross multiplication method:−17+21u = −14+17v = 3−21 4u =1 and 3v =1u=4 and q=3x=1/4 nad y=1/3 [Since we consider p=1/x and q=1/y]Answer x=1/4,y=1/3(i) 2(3−2x)=13⇒ 6−4x=13 ⇒ 4x=6−13=−7⇒ x= 4−7 (ii) 2x =5+ 3x ⇒ 2x − 3x =5 ⇒ 63x−2x =5⇒ 6x =5 ⇒ x=30 (iii) 7(x−2)=2(2x−4)⇒ 7x−14=4x−8 ⇒ 3x=6⇒ x=2 (iv) 3x− 31 =2(x− 21 )+5⇒ 3x=2x−1+5+1/3⇒ x=4+ 31 ⇒ x= 313 I don't know 4th questions answer sorry

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The answer should be c.