Any MATHEMATICIANS IN THE HOUSE PLS Find the equation of the circle centre (-3,4) with radius 7 units

options
(a) x2+y2+6x+8y−24=0
(b) x2+y2-6x-8y+24=0
(c) x2+y2+6x-8y-24=0
(d) x2+y2+6x-8y+24=0

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

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