Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,000 and $40,000. Assume that a 95%
confidence interval estimate of the population mean annual starting salary is desired.
a. What is the planning value for the population standard deviation?
o =
b. How large a sample should be taken if the desired margin of error is $400? Round
your answers to next whole number.
150
$270?
$100?
X
c. Would you recommend trying to obtain the $100 margin of error? Explain.
No, the sample size would probably be too time consuming and costly.
How would I work this out?

d) -1

step-by-step explanation:

answer: options

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt