What value of x satisfies the equation 1/2 x-5(x-1/3)=5/4 x+3

this is the answer....

x - (5 -sqrt149 ) / 4  and x-  (sqrt149+5)/4   = = x - -4.3016389  and x - 4.3016389

Step-by-step explanation:

1/2 x-5(x-1/3)=5/4 x+3 = ( 1/2x^2-5x -1/6x -5/3)  = (5/4x+3)  = ( 1/2x^2-6 5/6)  = (5/4x+3)  convert 5/4 to  12ths = *3 =  15/12  and 5/6 * 2 = 10/12 =  ( 1/2x^2-6 10/12)  = (15/12x+3)  = 1/2 x^2 - 15/12x -6 10/12 - 3 = 0   = 1/2 x^2 - 15/12x -3 10/12 = 0 then multiply by 2 to make 1/2 whole 1/2 x^2  (2)- 15/12x (2) -3 10/12 (2) = 0 =  x^2 - 30 /12x -6 20/12 (2) = 0  simplify irregular fraction  x^2 - 2 2/4x  -7 3/4  = 0  then do the abc quadratic formula = x - (5 -sqrt149 ) / 4  and x-  (sqrt149+5)/4   =  x-  -17.2065556/4   = x - -4.3016389    and 17.2065556/4 =x - 4.3016389

what is the question here

step-by-step explanation:

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