Given f(x)=3x−3 and g(x)=2x−3

f(3)−g(5)+12=

When f(x) = 3x - 3 and g(x) = 2x - 3,

f(3) - g(5) + 12 = 11.

Step-by-step explanation:

Given:

f(x) = 3x - 3

g(x) = 2x - 3

First solve f(3).

f(x) = 3x - 3

Substitute input value.

f(3) = 3(3) - 3

Multiply 3 and 3.

f(3) = 9 - 3

Subtract 3 from 9.

f(3) = 6

Next, solve g(5).

g(x) = 2x - 3

Substitute input value.

g(5) = 2(5) - 3

Multiply 2 and 5.

g(5) = 10 - 3

Subtract 3 from 10.

g(5) = 7

Knowing these values, solve the expression.

f(3) - g(5) + 12

Replace functions with their values.

6 - 7 + 12

Subtract 7 from 6.

(-1) + 12

Add -1 and 12.

11.

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

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c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.