Erica makes necklaces from beads. Each necklace consists of blue, white and green beads in the ratio of 6 : 4: 1 One necklace needs to have 44 beads. How many of each type of bead is needed to make the necklace?

For one Necklace you would need...

24 blue beads.

16 white beads.

4 green beads.

Ratio: 24: 16: 4

Step-by-step explanation:

If you quadruple the amount of beads from the original amount (6 : 4: 1), the total beads for that necklace will be 44.

Step 1: 6 x 4 = 24 (amount of blue beads in necklace).

Step 2: 4 x 4 = 16 (amount of white beads in necklace).

Step 3: 1 x 4 = 4 (amount of green beads in necklace).

Now check to see if the total of all types of beads sum up to 44:

Step 4: 24 + 16 + 4 = 44

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There is your

You need 24 blue beads, 16 white beads, and 4 green beads to have a total sum of 44 beads in that one necklace.

a

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)