In the graph, the area below f(x) is shaded and labeled A, the area below g(x) is shaded and labeled B, and the area where f(x) and g(x) have shading in common is labeled AB. Graph of two intersecting lines. The line f of x is solid and goes through the points 0, 4, and 4, 0 and is shaded below the line. The other line g of x is solid, and goes through the points 0, negative 1 and 2, 5 and is shaded below the line.

The graph represents which system of inequalities?

y ≤ −3x − 1
y ≤ −x − 4

y > −3x + 1
y ≤ −x − 4

y < 3x − 1
y ≤ −x + 4

y ≤ 3x − 1
y ≥ −x + 4

y ≤ 3x − 1, y ≤ −x + 4

Step-by-step explanation:

The line f(x) is solid and goes through the points (0, 4) and (4, 0) and is shaded below the line.

The line that satisfies the point (0,4) and (4,0) is y=-x+4

Since it is shaded below the line, we have the inequality sign:

Therefore, one of the lines is:

The line g(x) is solid and goes through the points (0, -1) and (2, 5) and is shaded below the line.

Slope,

When x=0, y=-1

y=mx+b

y=3x+b

-1=3(0)+bb=-1

Therefore, the equation of the line is:

y=3x-1

Since it is shaded below the line, we have the inequality sign:

Therefore, the other line is:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation