A circle passes through the vertices of a square of side 20cm. Find the radius of the circle.

14,1 cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

14.1cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

the function makes a strait line horizontally with no x intercept but a y intercept at 9.

pretty sure 750 each month!

step-by-step explanation: