Can anyone help(pwease) Barry owns a house on a river. The river flows at 3 km/hr. Barry
decides to start rowing downstream, with the current, at noon. He
wants to return to his house at 5 p. m. At what time should Barry turn
around and row home if he normally rows 5 km/hr in water that has
no current?

I am struggling;-;

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

For f(x) = 3x+1 and g(x) = x2 - 6, find (g/f)(x)

Two triangles can be formed with the given information. use the law of sines to solve the triangles. b = 49°, a = 16, b = 14