In Diagram 14, the points P and Q have position vectors p and q respectively. OP is produced to R such that OR = 30P and OQ is produced to such that os 400. The lines PS and QR intersect at point T. (a) Express PS and QR in terms of p and q.
(b) Given PT = hPS and OT = kQR, express OT
(i) in terms of h, and q.
(ii) in terms of k, p and q.
(c) Hence, determine the values of h and k.

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )