Determine whether each relation is a function (2,4),(3,5),(4,6),(5,8) (1,4),(2,3),(3,-6),(-3,6)
(1,5),(1,7),(1,-5),(1,-7) (0,4),(1,4),(2,4),(3,4)
x^2=y+1
xy=1
x=3
y=-2

Step-by-step explanation:

(2,4),(3,5),(4,6),(5,8) (1,4),(2,3),(3,-6),(-3,6)

is NOT a function, because some x values (2 and 3) have more than one associated result value (4, 3 and 5, -6).

(1,5),(1,7),(1,-5),(1,-7) (0,4),(1,4),(2,4),(3,4)

is NOT a function as the x value 1 has more than 1 associated result values (5, 7, -5, -7, 4).

x² = y + 1

y = x² - 1

this is a function. for any value of x we get exactly one result value.

xy = 1

y = 1/x

this is a function. for any value of x we get exactly one result value. but we do need to exclude x=0.

if we cannot do that, then it is NOT a function, because x=0 has no associated result value.

x = 3

is NOT a function, because although there is only one valid x value (3), there are infinitely many possible y result values associated with this x value (y can be "anything").

y = -2

this is a function. for any value of x we get exactly one result value (constantly -2).

1/4 because there is 4 grades.

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )