Consider the line y=-2/3x-4 Find the equation of the line that is perpendicular to this line and passes through the point (-3,2)

Step-by-step explanation:

Perpendicular lines have negative reciprocals slopes, in which the product of their slopes result in -1.

Since the slope of the given line is m1 = -2/3, its negative reciprocal must be m2 = 3/2:

Next, we'll use the slope of the other line, m = 3/2, and the given point, (-3, 2) to solve for the y-intercept of the other line by substituting the values into the slope-intercept form:

y = mx + b

Add 9/2 to both sides to isolate b:

Therefore, the equation of the line perpendicular to is:

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)