find the slope of the line that is (a) parallel and (b) perpendicular to the line through the pair of points (-6,-1) and (1.7)

Step-by-step explanation:

1.  Calculate the slope for the line with points (-6,-1) and (1,7).  Rise/Run, so take the difference between the two points for both x and y:

  Change in x (the run) is 1 - (-6) = 7

   Change in y (the rise) is 7 - (-1) = 8

The slope is rise/run so 8/7.

Any line of the form y=mx+b, where m is the slope, will be parallel to this line if it has the same slope:  y = (8/7)x + whatever.  

Any line in the same format with be perpendicular if the slope is the negative inverse of the reference line.  In this case the perpendicular slope would be (-7/8).  y = (-7/8)x + whomever.

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

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step-by-step explanation: