The diagonals of a rhombus measure 16 cm and 30 cm .find its perimeter ( in easy way)?

tokfodmzjksslpsspzkka

Step-by-step explanation:

Let ABCD be a rhombus, all sides of the rhombus have equal length and its diagonal AC and BD are intersecting each other at a point O.

As we know that the diagonals in the rhombus bisect each other at 90°.

So, AO can be written as (AC/2)  

= 16/2  

= 8 cm

And, DO can be written as (BD/2)

= 30/2  

= 15 cm

Then, consider the triangle AOD and apply Pythagoras theorem,  

AD2 = AO2 + DO2

AD2 = 82 + 152

AD2 = 64 + 225

AD2 = 289

AD = √289

AD = 17 cm

Hence, the length of each side of the rhombus is 17 cm

Now,

The perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

Therefore, the perimeter of the rhombus is 68 cm.

i dont know their was no answer choice jiggaboo

(im black)

step-by-step explanation:

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)