Jacob went bowling over the weekend. On Saturday, he bowled at Bowlero, where he rented shoes for $3.25 and paid $3.75 for each game. On Sunday, he bowled at the
Cowtown Bowling Center, where he rented shoes for $2.50 and paid $4.00 per game. If
he spent the same amount each day, how many games did he bowl? (Let the number of
games played = x.)

x= 3

Step-by-step explanation:

Blowlero's cost of shoes + the cost of one game = $7.00. If we add the cost of a game two more times, we get $14.50

At Cowtown Bowling Center, we can do the same thing. The cost of shoes + the cost of a game= $6.50. If we add the cost of a game two more times, we get $14.50.

For Jacob to have spent the same amount each day, he would have had to played three games at both places.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

idk

step-by-step explanation: