HELP ASAP I NEED THIS IN ONE HOUR WILL REPORT WRONG ANSWERS A new drill is used to dig a hole in the ground. At noon, the hole is 13.2 feet deep when the new drill is turned

on for the first time that day. At 2 p. m., the drill has dug the hole to be 42 1/4 feet deep. The new drill dug

1.5 times as much of the hole as the old drill would have in the same length of time.

(a) What expression represents the number of feet the new drill dug?

(b) How many feet would the old drill have dug in the same length of time? Show your work. Answer the
question in a complete sentence.

(a) 42.25 - 13.2

(b)  The old drill would have dug 19.367 ft in the same length of time (2 hours).

Step-by-step explanation:

(a) In the two hours, 12 Noon to 2 p.m., the new drill dug

42.25 - 13.2 =

29.05 feet.  

(b) Let r = the old drill dig rate in units of ft/hour

Then, 1.5r = the new drill dig rate.

So, 1.5r (2 hours) = 29.05, so that

r = (29.05)/(1.5 * 2) = 9.6833333 ... ft/hour.

So, the answer is: 9.683333 ... * 2 = 19.367 ft, rounded to the nearest 1000th.  Thus, the old drill would have dug 19.367 ft in the same length of time (2 hours).  

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.