If f(x) is defined as follows, find (a) f(-3), (b) f(c), and (c) f(1). if x<0
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mi
x²
f(x) = { 0
h = 0
2x + 2 if x>0
(a) f(-3) = (Simplify your answer.)
.
(b) f(0) = (Simplify your answer.)
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(c) f(1) = (Simplify your answer.)

Which of the following values cannot be probabilities? 0.08, 5 divided by 3, startroot 2 endroot, negative 0.59, 1, 0, 1.44, 3 divided by 5 select all the values that cannot be probabilities. a. five thirds b. 1.44 c. 1 d. startroot 2 endroot e. three fifths f. 0.08 g. 0 h. negative 0.59

Last one and the bottom answer choice is y=(x-4)^2+1 you guys!

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x -4 0 for x? cos -3+ v (3) 2-4() 2(5) 3+ |(3)² +4() 205) 3+ (3) 2-4() -3+ v (3)² +4()