An organization tracking college expenses reported that the average cost of textbooks and supplies for students attending four-year public colleges and universities in the 2015-16 academic year is . Suppose a sample of 15 students was selected and the accompanying data reflect the amount they paid for textbooks and supplies during that year. $1,358 $1,204 $1,207 $1,062
$1,316 $1,38 $1,554 $1,501 $1,421
$1,398 $1,223 $1,382 $1,542 $1,176

Required:
a. Calculate the mean and standard deviation.
b. Determine the number of standard deviations the most extreme cost is away from the mean. If someone were to advise a prospective student concerning the money the student should save to afford the cost of books and supplies for one year for at least 90% of the colleges, determine the amount they would suggest.

i can't read the graph

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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