An ingot of metal shaped like the triangular prism below has a total mass of 25.6 kilograms. What is its density in grams per cubic centimeter.

453

Step-by-step explanation:

9514 1404 393

  20 g/cm³

Step-by-step explanation:

The volume of the prism is the product of the area of its triangular base and its height. The triangle area is ...

  A = 1/2bh

  A = 1/2(16 cm)(8 cm) = 64 cm²

The height of the prism is 20 cm, so its volume is ...

  V = Bh = (64 cm²)(20 cm) = 1280 cm³

The density of the ingot is the ratio of its mass to its volume.

  ρ = M/V = (25,600 g)/(1280 cm³) = 20 g/cm³

The density of the ingot is 20 g/cm³.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

∠cbe and ∠deb are same-side interior angles.

i took the test