I don't know how to do this... Write an equation for a parabola with x-intercepts (-4,0) and (2,0) which passes through the point (1,-10).

y=2x^2+4x−16

Step-by-step explanation:

Assume that the equation of the parabola is y=ax2+bx+c.

Since the parabola passes through the point (−4,0), then 0=16a−4b+c.

Since the parabola passes through the point (2,0), then 0=4a+2b+c.

Since the parabola passes through the point (1,−10), then −10=a+b+c. Thus, we have obtained the following system:

Solving it, we get that a=2, b=4, c=−16. Thus, the equation of the parabola is y=2x^2+4x−16.

x = -2

y = 848

step-by-step explanation:

plug in the numbers