Find three consecutive integers such that twice the first is equal to 17 more than the largest number

smallest is X

middle is X+1

largest is X+2

2X = x+2 + 17

2X = x + 19

x = 19

19. 20, 21

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

i dony know

step-by-step explanation: