The length of a rectangle is 8 cm more then 4 times the with. If the perimeter of the rectangle is 46 cm, what are the dimensions

15

Step-by-step explanation:

let the breadth be x

let the length be x+8

perimeter of rectangle=2 (length +breadth)

so, 2 (x+x+8)=44cm

=2 (2x+8)=44

=4x + 16=44

=4x= 44-16

=4x= 28

=x = 28÷4

=x= 7

therefore,

breadth is 7 (x)

length is 7+8 (x+8)

=15

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

hiking down a winding trail.

step-by-step explanation: