In a batch of 8000 clock radios 5% are defective. A sample of 13 clock radios is randomly selected without replacement from the 8,000 and tested. The entire batch will be rejected if at least one of those tested is defective. What is the probability that the entire batch will be rejected

Step-by-step explanation:

P(A)=1−P(not A)

We can use this here. Event A is that the clock is defective, so Event (not A) means the clock works.

0.02=1−P(not A)

P(not A)=0.98

Therefore, for all the clocks to pass, the probability is P(not A)11.

Now again, we can use complementary counting.

(probability of all clocks failing) = 1 - (probability of all clocks passing)

Probability of all clocks failing = 1−P(not A)11

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

it would open into a square depending on the type of envelope i’m not sure about the second part