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x + y =5 eqn (1)

x - y =3 eqn(2)

using substitution method

x + y = 5

-

x - y = 3

0 + 2y=2

y = 2/2

y = 1

substitute y in egn(1)

x + 1 = 5

x = 5-1

x = 4

then (x, y) = (4,1)

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions