Please help quick! Find the value of x to the nearest tenth.

3.3

Step-by-step explanation: pythagorean theorem.

first we'll do the bottom triangle. a^2 + b^2 = c^2

a=3 and b=4

(3)^2 + (4)^2 = 9 + 16 = 25 which = c^2

to find c from c^2, square root the c^2 value. in this case it's 25. the square root of 25 is 5.

5 is now the base of the rectangle

now we can do pythagorean theorem again. except we'll switch it so it's c^2 - b^2 =a^2

c=6 and b=5

(6)^2 - (5)^2 = 36 - 25 = 11 = a^2

to find a we'll square root 11 which is just . approx. 3.3 to the nearest tenth.

We can use the Pythagorean theorem to solve for x.

But first, we have to find the value of 'a' (as I labelled in the diagram below). We could actually do all this in one step if we set it up correctly.

so    x = √(6² - a²)

&     a² = 3² + 4²

⇒  x = √[6² - (3² + 4²)]

    x = √(11)   or ≈ 3.3167

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it