For a function f, we are given that f(8) = 1 and f'(8) = 2. What's the equation of the tangent line to the graph of f at x = 8?

Step-by-step explanation: y

'

(

x

)

=

1

f

'

(

f

−

1

(

x

)

)

y

'

(

−

8

)

=

1

f

'

(

f

−

1

(

−

8

)

)

y

'

(

−

8

)

=

1

f

'

(

2

)

y

'

(

−

8

)

=

1

−

3

(

2

)

2

−

1

y

'

(

−

8

)

=

1

−

12

−

1

y

'

(

−

8

)

=

−

1

13

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet