A 10-inch-by-11-inch transparency sheet is placed on an overhead projector. If the projector enlarges 300%, what will be the lengths of the sides of the projection? How does the perimeter of the original transparency sheet compare to the perimeter of the projection? For the lengths of the sides of the projection, I got 30 inches by 33 inches. But what about the second part of the question? I’m not sure how it compares.

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

3

step-by-step explanation:

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt