HELP due by 9pm tonight New Zealand time !! I asked this but someone was not correct and it was very confusing Round 10,879 to the nearest ten thousand, thousand, hundred and ten

round 52,864 to the nearest ten thousand, thousand, hundred and ten

Round 10,879 to the nearest ten thousand, thousand, hundred and ten

Round 77,329 to the nearest ten thousand, thousand, hundred and ten

Round 10,879 to the nearest ten thousand, thousand, hundred and ten

Round 77,329 to the nearest ten thousand, thousand, hundred and ten

Round 10,879 to the nearest ten thousand, thousand, hundred and ten

Round 65,536 to the nearest ten thousand, thousand, hundred and ten

1.) 10000

11000

10900

10880

2.) 50000

53000

52900

52860

3.) (repeat of 1.)

4.) 80000

77000

77300

77330

5.) (repeat of 1.)

6.) (repeat of 4.)

7.) (repeat of 1.)

8. 70000

66000

65500

65540

1. 10879.0000

2.52864.0000

3. 65536.0000

4.77329.0000

Step-by-step explanation:

They are all the same but just keep adding zeros.

(Hope this helps can I pls have brainlist (crown)☺️)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i believe the answer is letter c) 8

step-by-step explanation: